Note on the Three-Point, or Pothenot's, Problem. 



53 



Example. 



A -1811-59 -1018-55 y'= -1376-55 x' 

 B + 6-81 -930-26 y" = + 441-85 x" 

 C- 435-04 -1425-45 0-00 



„ = 64-7-40 



^ = 20-33-20 



+ 9-685719 

 + 2-609488 



+ 2-295207 



+ 197-34 



-/ + 1376-55 



A+ 1573-89 



A + 3-196974 

 m 9-102482 



+ 2-299456 

 -wA- 199-28 

 + B -260-69 



-459-97 



+ 9-685719 

 -3-1 38792 



-¥824511 



-667-59 



+x' + 406-90 



B- 260-69 



-2-662730 

 0-006906 



.r-2 : 655824 

 9 102482 



y -1-758306 



+ 0-425980 

 + 2-694772 



+ 1320-54 

 + y" + 441-85 



C+ 1762 -39 



A + 1573-89 



+ 3336-28 



2-625744 

 3-523262 



m 2 + l 



-+406-90 



= +495-19 



0-00 



+ 0-425980 



+ 2-645275 



+ 3-071255 



+ 1178-30 

 .r" -495-19 



D + 683-11 

 B- 260-69 



+ 422-42 



^9-102482 

 7^8-204964 



=Toi603 



y-57-32 x-452-71 

 -435-04 -1425^45 



Co-ordinates of P : -492-36 -1878-16 



A check is afforded by the computation of the angles of direction 

 P A and P B. P C is given by 



tan—- 1 m. 



March, 1898. 



