388 SCHULTÉN 
dont la résolution donne 
2) (E-m (ms) s(1-+4+mt) Æ [AA E-m)(ms=h9+s(1+ Fm) Ÿ— 
(A(-R (ms ROSE) ) (AAA (Em (1-43) )]( 
DA (SA (Em — (14 m)], | 
c'est-à-dire, puisque 
(AAE-m)(ms-k9 +1 + m2) PP (RAR RAS RD) 1-+R2-mt)) ((S-K 2 
+R{tm}-(1+4+ më)) = (14 + m°)[25(t-m)(ms—kt}+(s—k)"+ (ms) 
A Ce Ce CD Co C1 
+(s—k)(ms—kt)*] 
= (142 +m°) Lms—kt+s(em) Ÿ+ (s—kÿ4s(s—)?| 
— (SAP Ts (em) (ms —Kt)] 
= (LH RE ME) LE(S — RP + (S — A) + (5 —kŸ] 
hs RAS m0 (Em) (LÉ )] 
= Ps —k) [+R mn) (14-46) +R (1H ks mt)? 
— là (4 +R nm) (+ S +] 
= R(s-k) CR (14%s-+mt) +172) (44m (148 + 0)], | 
=) ms —kt) (14422) Es — 4) RS mt) (1 —R2) 142 Hn2)(1+452 + 2) 
Rs —k 3+R2(t—m)2—(1#A2Hm2) 
Donc 
BR + (ET | 
__ ms—kt —R2(t—m)2{(ms—kt) — s(t—m)(1H4k2Lm2 \ 
me PA m) VLA(14s--mb + 
(4m) (ANT: CAM (S—- RER (em) — (148 mt )] 
= mener + Alt-m)V [A(1+ks-+mt)" 
+ (1—27) (1+k%+m?) (1 +s+2)]8 : [2% (s—k) + (tm) —(1+47+m°)] 
