112 INJUEY, EECOVEEY, AND DEATH 



87.10 to 64.18. It was then replaced in sea water. The 

 recovery curve may be calculated as before, the only 

 differences being as follows : 



1. On replacing the tissue in sea water the destruction 

 of (by the reactions N — >-0 — >P) ceases (or becomes 

 negligible) ; hence the value of at the beginning of the 

 second exposure (if equilibrium has been reached) is 

 that of the obsert^ed resistance less 10, or 87.10 — 10 = 

 77.10. We find by means of formula (5) that when at 

 the start equals 90 it loses 11.95 during an exposure of 

 21.2 minutes to the solution of NaCl, but as it only equals 

 77.10 at the start the loss will be 11.95 (77.10^ 90) = 

 10.23. Subtracting this from 77.10 gives 66.87, the value 

 of at the end of the second exposure, and adding 10 

 (since the base line is 10) makes 76.87, the level to which 

 the resistance should rise after the second exposure. 



2. At the start of the first recovery^* 8 is rapidly con- 

 verted into A, but is partially restored during the 

 subsequent stay in sea water and at the beginning of the 

 second exposure equals 2.7 (O-j-90) in which has the 

 value given above (77.10). 



3. During exposure to NaCl the value of R diminishes 

 from R^ to Ri according to the formula 



-KrTe -(0.0498)42 



fii=J?oe = 1041.77 e (8) 



in which i2o = the value of R before the first exposure 

 (1041.77) and T^ equals the total exposure to NaCl (20.8 

 + 21.2 = 42). 



It is evident that unless R is restored during the 



" If the value of were 90, S would be completely restored to its orig- 

 inal value of 2.7, but since has fallen to 77.10 it can only restore S to 

 2.7 (77.10 H- 90). 



