86 PROFITABLE PIGEON UREEDlNG 



cock's l)loocl represents 1 and the hen mated to him is %. 

 These two added together and divided by two gives us Yg. Thus 

 we are more firmly estaljlishing a strain composed mainly of 

 the blood of the original cock and breeding out the blood of the 

 original hen. On the other side of the chart we see that we 

 are doing the opposite with another strain. To maintain our 

 original 1/2 blood we mate a cock from i to a hen from 5 and 

 we get group 7 ^^'hicll is 14 blood or the (equivalent of group 3 

 in a later generation. By this fmie the orignal cock and lien 

 may have to be discarded or be too old. Therefore we breed our 

 best hen from group 6 back on to a cock from 4 and we get 

 group 9 wbicli gives us lo-Ki blood from the original cock be- 

 cause the cock from 4 was ^4 of his blood and the hen from 6 

 was Ys- These two fractions added together gives us 13-S and 

 1/2 of ^^'hich is 13-16. By mating a code from 8 with a hen from 

 5 we get group 13 which contains 13-10 of tlie blood of the 

 original lien 2. At this point we again mate to get more Yo 

 blood birds and we do this by mating birds from 6 and 8 as 

 shown. (Notice the line running out of the bottom of group 6 

 and line from group 8 meeting lielow 7 and running into group 

 11.) Now we mate a cock from (i to a Y2 lilood hen from 7 and 

 the I'esult is group 10 which i('[irescnts youngsters containing 

 11-16 of the blood of the original cock 1. Like\^■isc «e mate a 

 cock from 7 back to a lii'ii from N and \\'e get group 12 which 

 is 11-1() of the lilood of the original hen 2. At this point we 

 select a cock from our male line in grouji and mate him to a 

 hen from group 13, our female line, and get group 16 thus 

 maintaining Y2 I'loods. Group 14 is obtained by mating a cock 

 from group 9 to a hen from group 11, fiie cock in this case being 

 1,3-16 and the hen Y2 or 8-16 and the resultant Y2. of the sum of 

 these two gives us 21-32 of the original lilood of cock 1. On 

 the other hand we obtain group 18 liy an opposite mating on 

 the female line using a hen out of grouji 13 mated on a cock 

 out of group 11. Thus wi' are gradually eliminating the original 

 cock's blood on one side and tlie original hen's blood on the 

 other. By mating a hen from our gi'oup 10 to a cock from G 



