CREAMERY PROBLEMS. 279 



Explanation : First find the amount of butter fat 

 in the milk and from that subtract loss, which is 

 12.5; this leaves 987.5 lbs. butter fat in the cream. 

 Each 100 lbs. of cream contains 30 lbs. butter fat, 

 and there will be as many 100 lbs. of cream as 30 

 is contained in 987.5, and the total cream will be 

 100 times this number, or 3,291.66 lbs. cream. 



Problems for Practice. 



Find the approximate, amount of cream when 

 losses incident to separating are in each case 1^ per 

 cent of the total fat in milk. 



62. To iind amount of skim milk from any quan- 

 tity of milk. 



Problem: A creamery receives 24,000 lbs. of 

 whole milk; 80 lbs. of skim milk out of every 100 

 lbs. of milk are returned to patrons. How much 

 skim milk does the creamery return to patrons? 



Rule: Multiply milk pounds by per cent of skim 

 milk returned and divide result by 100. The quo- 

 tient is number of skim milk pounds. 



Solution: 24,000X80-^1,920,000; 1,920,000-^100= 

 19,200 lbs. Ans. 



Explanation: For every 100 lbs. of whole milk 

 delivered the patron gets 80 lbs. of skim milk. The 

 total skim milk will be (24,000X80)-=-100=19,200 

 lbs. 



