50 



Sections 3569 and 3570 of the Revised Statutes of the United States read 

 as follows : 



"Sec. 3569. It shall be lawful throughout the United States of America to 

 employ the weights and measures of the metric system ; and no contract, or deal- 

 ing, or pleading in any court, shall be deemed invalid or liable to objection 

 because the weights or measures expressed or referred to therein are weights or 

 measures of the metric system. 



"Sec. 3570. The tables in the schedule hereto annexed shall be recognized in 

 the construction of contracts, and in all legal proceedings, as establishing in 

 terms of the weights and measures now in use in the United States, the equiva- 

 lents of the weights and measures expressed therein in terms of the metric 

 , system ; and the tables may lawfully be used for computing, determining,, and 

 expressing in customary weights and measures the weights and measures of the 

 metric system." 



* * * * 3t * "* 



A meter is equal to 39.37 English inches. 



A cubic meter is equal to 1.308 cubic English yards, or 35.316 cubic English 

 feet. 



A liter is equal to 1.0567 liquid quarts. 



A kilogram is equal to 2.20462 pounds, avoirdupois. 



A quintal is equal to 220.46212 pounds, avoirdupois. 

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The volume of all timber in accordance with the provisions of section twelve 

 of The Forest Act will be determined as follows: 



Bound Umber. — ^Multiply the area of the smaller end by the length of the log. 



JO Bitiers 



Example: Length, 10 meters: circumference of smaller end, 90 centimeters or 

 .90 meters. .90 X .90 X .08 X 10 = .648 cubic meters. 



Square timber. — Multiply the average cross section by the length, to which 

 twenty-five per centum shall be added for loss in squaring. 



Example: Widtli of average cross section, 50 centimeters; thickness of 

 average cross section, 45 centimeters: length, 12 meters. .50 X -45 X 12^ 2.7 

 cubic meters. 25 per cent of 2.7 = .675. 2.7 -t-. 675 = 3. 375 cubic meters. 



The volume of approximately octagonal logs ( four sides being hewn and the 

 other four unhewn) will be ascertained by multiplying eight-tenths of the square 

 of the average diameter connecting the two pairs of opposite unhewn sides of 

 the small end by the length. 



K 



v: 



Example: Average diameter between opposite unhewn sides of smaller 

 end, 51 centimeters; length, 14 meters. .51 X .51 x .8 X 1-1 = 2.913 cubic 

 meters. 



