COMPUTATION OF RATIONS 79 
The 100 pounds of corn stover contains: 
59.5 pounds of dry matter 
1.4 pounds of protein 
31.2 pounds of carbohydrates 
0.7 pounds of fat 
Tf 100 pounds of corn stover contains these quantities of digestible 
nutrients, then 1 pound contains just one one-hundredth as much, or 
the following quantities: 
.595 pounds of dry matter 
.014 pounds of protein 
.324 pounds of carbohydrates 
.007 pounds of fat 
Ten pounds will contain ten times the quantity of 1 pound, or the 
following: 
5.95 pounds of dry matter 
.14 pounds of protein 
3.24 pounds of carbohydrates 
.07 pounds of fat 
The digestible nutrients in 30 pounds of corn silage are ascer- 
tained in the same manner: In 
In100lbs. Inilb. 301bs. 
Dry matter —_ 20.9 + 100 = .209 X 30= 6.27 
PROteIMe oor she ee pe ee 0.9 +100 = .009 X 30=— Rh 
Carbohydrates _-------------------- 12.6 + 100 = .126 K 30 = 3.78 
UB Sa eer Sete mle a wine ea 0.6 — 100 = .006 KX 30=_~—Ss:«118 
Making the same computation for each constituent in clover hay, 
we have the following: In 
In100lbs. Inilb. 30 lbs. 
Dry matter - sec - 84.7 +100 = .847 & 15 = 12.70 
Proteitt-.2s2222-22207 so nec20 so sote 7.1+—100 = .071 KX 15= 1.06 
Carbohydrates ~------------------- 37.8 +100 = .378 KX 15= 5.67 
Patrsact asec ee eee 13-100 = 18 Miss 27 
7. Comparing trial ration with the standard—If we 
arrange these figures in a table and add the nutrients to- 
gether, we shall have a statement of the quantity of each 
constituent supplied, and will be in a position to compare 
their totals with the standard, to know what nutrients 
are insufficiently provided. This is done as follows: 
