(14) DAIRY RULES (Continued) 



mixture wanted, and the rest, or 20 per cent, equals the amount that must 

 be added as skimmilk. 20 per cent of 300 = 75. 300+75 = 375 pounds of 

 the standardized milk. 



12. Where milk is to be raised to a higher per cent of fat by adding milk 

 or cream of a still higher fat content. 



Subtract the percentage of fat in the milk on hand which contains the 

 lower fat content from the percentage desired in the standardized product. 

 Take the difference between the percentage of fat in the milk or cream of 

 the higher fat content and the desired percentage of fat in the standardized 

 milk. Divide the first result by the second, and the result represents the 

 part of the milk or cream of the higher per cent fat to be used. Multiply 

 this result by the pounds of milk which contains the lower per cent fat, and 

 this will give the amount of the richer milk to add. This, added to the amount 

 of the milk with the lower fat content, will give the total amount standardized. 

 Thus: 



300 pounds of 3 per cent milk is to be made to test 3.5 per cent by adding 

 5 per cent milk. (3.5 per cent — 3 per cent = .5; and 5 per cent — 3.5 per 

 cent = 1.5); .5H-1.5 = .33 1/3; 300 X.33 1/3 = 100. Use 100 pounds of 5 per 

 cent milk with 300 pounds of 3 per cent milk, or a total of 400 pounds of 

 3.5 per cent standardized milk. 



13. By dividing the per cent of fat in the standardized milk into the 

 percentage of fat in the milk on hand and multiplying the result by the num- 

 ber of pounds of the milk on hand will give the number of pounds of the 

 standardized milk which can be made from the milk on hand. If the quantity 

 of the standardized milk is less than the amount on hand, then the difference 

 must be taken out as skimmilk; if greater, it must be added as skimmilk. 

 To illustrate: 



300 pounds of 3.5 milk will make how many pounds of 4 per cent milk? 

 3.4-=-4 = .875; .875x300= 262.5 pounds of 4 per cent milk which can be 

 secured, or 300 — 262.5 = 37.5 pounds of skimmilk to be removed. 



14. When it is desired to determine the number of pounds of standard- 

 ized milk a quantity of milk of a lesser per cent of fat will make. 



Find the pounds of butterfat in the quantity of milk by multiplying 

 the pounds of milk by the per cent (point fat off two places). Then by 

 dividing this result by the percentage fat desired in the standardized milk 

 and multiplying the result by 100 will give the number of pounds of stand- 

 ardized milk. Thus : 



• 300 pounds of 3.5 milk contains (300 x3.5 = 10.5) pounds fat. This 

 would make (10.5 -^ 4 xlOO = 262.5) pounds of milk testing 4 per cent. 



