FARM DAIRYING 449 



Problem 14 



Which of the following is the most profitable method of disposing of 

 milk testing 4 per cent fat : (a) at 3| cents a quart ; (6) to a cheese 

 factory at SI. 20 for 100 pounds (considering that 85 per cent of milk is 

 whey, which is returned and is valued at 15 cents for 100 pounds) ; 



(c) cream testing 21 per cent fat to a special trade at 18 cents a quart ; 



(d) cream testing 40 per cent fat to a creamery at 27 cents a pound for 

 the fat ; (e) to make butter on the farm and sell it for 30 cents a pound 

 and the buttermilk for 10 cents a gallon, overrun 12 per cent? 



In all cases consider the skimmed-milk to be worth 18 cents per 100 

 pounds. 



It must be noted that no allowance is made for waste or for cost of 

 handling. 



(a) 100 (lb. milk) -=- 2.15 (lb. per qt.) = 46.5, number of quarts in 100 



lb. milk 

 $.03i x 46.5 = $1.62. Answer. 



(b) 100 X .85 = 85, number of pounds whey in 100 lb. milk 



15 cents X .85 = 12 cents, value of whey 

 $1.20 (value of milk) + $.12 (value of whey) = $1.32. Answer. 



(c) 100 X .04 = 4, number of pounds fat in 100 lb. milk 



4 (lb. fat) -J- .21 (test of cream) = 19.04, number of pounds 



cream 

 19.04 -T- 2.115 =9, number of quarts cream 

 18 cents X 9 = $1.62 

 100 (lb. milk) - 19.04 (lb. cream) = 80.96, number of pounds 



skimmed-milk 

 $.18 (value of skimmed-milk per cwt.) X .8096 = $.14 

 $1.62 (value of cream) + $.14 (value of skimmed-milk) = $1.76. 



Answer. 



(d) 100 X .04 = 4, number of pounds fat in 100 lb. milk 

 $.27 X 4 = $1.08, value of fat 



4 (lb. fat) -T- .40 (test of cream) = 10, number of pounds cream 

 100 (lb. milk) — 10 (lb. cream) = 90, number of pounds skimmed- 

 milk 

 $ .18 (value of skimmed-milk per cwt.) X .90 = $.16 

 $1.08 (value of cream) + $.16 (value of skimmed-milk) = $1.24. 

 Answer. 



(e) 100 X .04 = 4, number of pounds fat in 100 lb. milk 



4 (lb. fat) -r- .30 (test of cream) = 13.33, number of pounds 



cream 

 4 (lb. fat) X .12 (overrun) = .48, number of pounds overrun 

 4 + .48 = 4.48 lb. butter 

 13.33 (lb. cream) - 4.48 (lb. butter) = 8.85, number of pounds 



buttermilk 

 1 gal. buttermilk = 8.7 lb. 

 2g 



