450 MANUAL OF MILK PRODUCTS 



Therefore, 8.85 lb. buttermilk = approximately 1 gal. 



S.10 X 1 = $ .10, value of buttermilk 



$.30 X 4.48 (lb. butter) = $1.34, value of butter 



100 (lb. milk) - 13.33 (lb. cream) = 86.67, number of pounds 



skimmed-milk 

 $.18 (value of skimmed-milk per cwt.) X 86.67 = $.15 

 $.10 (value op buttermilk) + $1.34 (value of butter) + $.15 



(value of skimmed-milk) = $1.59. Answer. 



butter problems (Guthrie) 



Computing overrun in butter. 



Overrun is the increase in the amount of butter made from a given 

 amount of fat, or it is the sum of the moisture, the salt, and the casein 

 of the butter minus the losses in manufacture. 



Problem 15 



(a) Butter-maker X has 1000 lb. of cream testing 35 per cent fat. 

 From it he makes 400 lb. of butter. Compute the percentage of 

 overrun and the value of the overrun at 25 cents a pound. 



1000 X .35 = 350, number of pounds fat 



400 (lb. butter) — 350 (lb. fat) = 50, weight in pounds of overrun 



50 -T- 350 = .142 



.142 X 100 = 14.2%, overrun. Answer. 



$.25 X 50 = $12.50, value of overrun. Answer. 



(b) Butter-maker Y is more careful in preventing leaks and wastes, 

 and he understands butter-making better than does X. From 1000 

 lb. of cream testing 35 per cent fat he makes 420 lb. of butter. Com- 

 pute the percentage of overrun and its value at 25 cents a pound. 



1000 X .35 = 350, number of pounds fat 



420 (lb. butter) — 350 (lb. fat) = 70, weight in pounds of overrun 

 70 -=- 350 = .20 



.20 X 100 = 20%, overrun. Answer. 

 $.25 X 70 = $17.50, value of overrun. Answer. 

 Butter.-maker Y has made from the same amount of fat $5 worth 

 more butter than has X. 



Problem 16 



Mr. Smith has a herd of ten cows, from each of which he receives 

 yearly 250 lb. of fat that he makes into butter. His average overrun 

 was 12 per cent until he bought apparatus for making a moisture test 

 and began to prevent some of his losses. His average overrun is now 



