from the Dimensions of Flat Drops and Babbles. 53 



so that we realize the portion ABCDE'E of the diagram 

 (fig. 3). Fig. 3. 



If the drop were of infinite radius, and therefore flat at the 

 top, the slab thus obtained would be equivalent to a similar 

 slab cut out of a mass of liquid, shaped as in fig. 4. If we 



Fig, 4. 



now, on this supposition, consider the equilibrium of the 



mass represented in fig. 3, with reference to horizontal forces 



parallel to its length, we can equate the hydrostatic pressure 



on the rectangular end to the sum of the tensions exerted 



along the two edges AD and BC. Thus writing, with 



Quincke, AB = K, and writing D for the difference between 



the density of the drop or bubble and that of the surrounding 



medium, K 2 D 



T + Tcos^=^: 



whence, when 0=0°, 



T= 



K 2 D 



Or, if we consider the equilibrium of that portion only of the 

 slab which lies above the horizontal section of greatest area 

 (see fig. 5), we may equate T to the hydrostatic pressure on 

 the rectangular area of unit breadth and depth (K — k), 



Fig. 5. 



1 6^- gj ^ 



whence 



T _ (K-£) 2 D 



2 



-3-T 



(1) 



