﻿498 
  Mr. 
  Nalinimohan 
  Basu 
  on 
  

  

  and 
  

  

  dv 
  dz 
  ) 
  ^Kds'ds* 
  ds'ds 
  2 
  ) 
  ' 
  ( 
  

  

  ds 
  c 
  ds 
  J 
  d 
  2 
  x 
  ,d 
  2 
  y 
  

  

  - 
  l 
  i$ 
  s 
  

  

  The 
  path 
  of 
  the 
  particle 
  must 
  therefore 
  satisfy 
  the 
  

   equation 
  

  

  dii 
  

  

  { 
  m 
  ™ 
  

  

  d 
  ) 
  dz 
  ds 
  

  

  ds 
  » 
  ds' 
  d 
  2 
  x 
  

  

  ds 
  

  

  ds 
  » 
  ds' 
  d 
  2 
  x 
  ,d 
  2 
  w 
  

  

  {/<?</ 
  (P.r 
  d.r 
  d-i/\ 
  \ 
  

  

  IM 
  \dsy? 
  ~ 
  Ts 
  ' 
  d?) 
  I 
  , 
  N 
  

   m 
  a?- 
  z 
  a? 
  .' 
  

  

  4. 
  The 
  problem 
  before 
  us 
  is 
  therefore 
  to 
  find 
  a 
  curve 
  

   whose 
  equations 
  will 
  satisfy 
  

  

  (i.) 
  The 
  initial 
  conditions, 
  

   (ii.) 
  The 
  equation 
  (1), 
  

   and 
  (iii.) 
  The 
  equation 
  (4). 
  

  

  Now 
  from 
  (1) 
  we 
  have 
  

  

  dX 
  ytana 
  __ 
  9 
  p 
  , 
  » 
  

  

  |f=i-(.^y-i)f. 
  

  

  1 
  r,i' 
  tan 
  a 
  T 
  >/ 
  -,1 
  

  

  