204 Dr. J. Prescott 'on the 



Now 



— .i-/i_ * , i 



3.U 4.7-4.7.8:11 J* 

 and, from the result of Case 3, 



Si= eS =4 ' 0122=16 ' 096 - 



The results of tedious arithmetic are 



7(50 = 0-3577, 

 ¥ / (s 1 )= -0-04344. 



Therefore 



0-3577 

 '~ 0-04544 b 



— *23 P A 



Kn 



Hence 



and 



= 5, 4-S. 



\Zi =1+ i7 1 



2 y/ Sl \' Sl 



Finally 



1 / 8-23P 1 /gv'EnOK \ 



" 2 x 4*012 \ " P^Kn / 



PZ2 = ^ X VEnCK 



= 4-012 [ VE^CK- 1-025 ISC \ . . (97) 



The critical Euler load for this beam, when used as a strut 

 and supported in the same way (fig. 14), is 



B=?5 - W 



