Inductance of Two Parallel Wires. 21 '3 



Similarly, due to B ; K (tA/o) originally leaving the secoud 

 wire, we have in the first an addition to A -f- C + . . . of 

 magnitude 



(B'K -p 2 B'X, a ~ +*£ B'K„V(1- W2 ) 



+ BV lf! ( Wl J!-V ! |)|'(l- ftft )'. . (99) 

 But 



pa. p pft p J y 



Adding the potential H = AJ (k-r) obtained in a previous 

 section, and reducing, the total potential in the first wire, 

 which contributes to the current, becomes 



where 



H =-]£! 1J ^>' <**» 



+ ^t~ o (wi^~*lp2^)j(l--P,Pl< 2 , . . (101) 



and the current is 



OT ' = ^- H ' n° 2 ) 



A similar expression may be written down at once for the 

 current in the second wire, and a formula for the self- 

 induction obtained. When the wires are similar in all 

 respects, 



H = i+( PlKo -vi 2 )£y ( i-^) 



_ 1-f-pi a 2 p, X { a 2 p! 



2 + *a " 



1-^2 V . x , K '^l-p 



