348 Dr. G. Bakker on the 



Substituting the values of p l} t\, v 2 , and v 3 , we find : 



Pvap. = 12-725 x 10 6 dyne per cm. 2 



To find a value for v mSiX , in the equation (16), we use the 

 equation (17) for the ease that the pressure is denoted by the 

 ordinate of the point C 8 . That gives : 



i+J— ?-. 



v l y max. Vk 



Hence 



'W. — 10 cm. 3 



The equation (16) gives therefore : 

 2(>ii q . - 10-528 x 10 6 ) x 1-7 = 2-197 x 10 6 (27'3 + 10), 



and we find 



p ]iq ^ = 34*63 X 10 6 dyne per cm. 2 ; 

 and further, 



pu q . -Pvap. = (34-63-12-72)10 6 = 21*91 x 10 G . 

 The equation of Kelvin, 



b- , j H 



jPliq. Pvap. 



gives thus : 



R = rcSo x 10_6 c,n (18) 



The H in this equation is the departure from the law of 

 Pascal in a spherical capillary layer and is different from the 

 •constant of Laplace, which corresponds to a plane capillary 

 layer. I shall, however, demonstrate that the value of H in 

 the equation (18) is of the same order of greatness as the 

 constant of Laplace. Indeed I have already observed that a 

 spherical drop has a liquid nucleus, which has a diameter of 

 the order of greatness of the thickness of a plane capillary 

 layer. The parts of the spherical capillary layer, which are 

 situated on opposite sides of the liquid nucleus, can also not 

 very much influence each other. That is to say, as a first 

 approximation we might consider our spherical capillary 

 layer as a part of a plane film of minimal thickness that is 

 rolled up. 



Also in the following way we see that the departure from 

 the law of Pascal in a spherical capillary layer, which limits a 

 drop of minimal size, has a value of the same order of greatness 

 as for a plane capillary layer. We have namely for the 

 capillary constant of Laplace and likewise more generally for 



