Results of Crystal Analysis. 



91 



For (Ti0 9 )«> we find as the best value a = lll 0, 5, and for 

 (Sn0 2 ) 3 «=112°-5. 



In the case of Sn0 2 it is only the (111) and (100 1 spectra 

 which can be used for the determination of « ; for the (110) 

 spectrum is very nearly normal regardless of the value we 

 give a, and the (101) spectrum is determined from a very 

 small face, which will cause the observed first-order spectrum 

 to be too weak. 



In Table VII. are given the values of A 2 and K and the 

 calculated and observed intensities. 



The agreement is a very good one ; thus the lattice given 

 in Table IV. can explain the typical distribution of intensi- 

 ties observed. 



Table VII. 



(TiO,) 2 , « = Hl°-5. 





(111) 







(101) 





*. 



A 2 . 



leal. 



lobs. 



k. 



A 2 . 



leal. 



lobs. 



100 



299 



100 



100 



100 



102 



100 



100 



20 



146 



98 



100 



20 



0-41 



8 



6 



7 



0-14 



0-3 







1-7 



515 



35 



11 



3 



7'55 



7*7 



5 



3 



2-13 



6 



1 





(100) 





(U0) 



100 



0-42 



100 



130 



100 



9-32 



100 



100 



20 



2-08 



98 



85 



20 



14-6 



31 



50 



7 



4-00 



66 



35 



7 



19-3 



14 



16 



3 



044 











3 



7-55 



2-4 



3 







(Sn0 2 ) 2 , 



*=1 



L2°5. 









(111) 





(100) 



100 



2-92 



18-5 



17 



1C0 



5-85 



100 



100 



30 



52-5 



100 



100 



30 



9-82 



51 



60 



12 



o-i 











12 



14-75 



30 



28 



5 



391 



125 



13 



5 



4-55 



4 



4 



