232 Method of finding Scalar and Vector Potentials, 

 is the solution of the equation 



V 2 A- ? |^=-p or UA=-p, 



and the solution of A = 



p— is 

 ' c 



a ( (C p u Ux ^ X ' ^11' dz' 



"JJJ w tog |g.[.(i-5)]'" 



with similar expressions for the solutions of the equations 



DA = -/ y and DA'=.-/A 



r c c 



These are the scalar potential and the components of the 

 vector potential at P. 



It would seem from the above, if correct, that for a single 

 charge e at Q moving in any manner the scalar potential at 

 any point P is 



eu 



where r = Q'P, and u is the velocity of Q', and the com- 

 ponents of vector potential at P are 



eu u x eu u y 



"ew-a 



If the square of - is neglected, we get the expressions 

 given by Lienard and Wiechert. 



