of the Electrons in the Neon Atom. 343 



Similarly resolving along the line e x e 2 we have 

 T 39*2 I _ <? eH e 2 l 



4c 2 'c~ U 2 2s* ' [(r + l) 2 + s 2 ]l 



eH 

 + ]>_]p"^]I + mG, 2 2 ^ + m <°* L 



Subtracting equations (II.) from (III.) we have 

 mc0 2 2 l — mo){ 2 l = ; 

 and therefore 6) 1 = co 2 . 



Replacing " g> 2 " by " c^ " in equation (I.) we obtain 

 TV 39eH _ e 2 M_ e 2 {r + l) 



\^ V V /l„3 — /I 72 + 0„3 "*" 



4c 3 "4Z 2 T 2s 3 ' [( r +l) 2 + » 2 ]l 



e 2 (r-l) 



|3 +277IO)! 2 /. 



Another equation is required before we can find a>i, g) 3 , 

 and " r." This equation can be found by finding the force 

 acting on electron " e 9 " along the line e 9 e 1Q , and equating 

 the total force to zero. 



Performing this operation we have 



10* 2 _ 4g 2 (r + Q 4**(r-l) * 9 



K J r 2 ' ~~ [(r + l) 2 + s 2 Y? [(r— J)MV]t + 4r» + ;* 

 Which may be expressed in the form 



,VT^ 9 2/ _39^_ 4^(r + Z) ±eH(r-l) 



iVi,)ZmWl 4r 3 r [(r + Z)>+y]l r[(r- Z) 2 + s 2 ]i' 



Substituting this value for 2moi> l 2 l in (IV.) and dividing 

 throughout by " e 2 " we obtain the equation 



l Vli -i 4 ^ c 3 Z 3 S 3j [( r+ ^2 +6 .'2-||^- L r | 



[(r-Z) 2 + s 2 ]f 1 ^ r j 4r 3 * 



This equation contains no unknown quantity except " r." 

 Now c = 6*5 x 10" 9 , .". 2=3-75 x 10" 9 and s = 5'31 x 10" 9 . 

 Putting these values for s, I, and c, we obtain the equation 



(Vim 1-04 xlO 17 - r + 3-75xl0" 9 



1 ; 1UiXlu -[(r + 3'75xl0- 9 ) 2 + 28'2xl0- 18 ]f 



f _ 15xl0~ 9 ) r-3-75xl0~ 9 



C l r ) [(r-3 7 75xl0- 9 ) 2 + 28-2xl0- 18 ]l 



( , , 15xl0" 9 J , 36-6x10-9 

 ( r } r 6 



