904" Dr. A. 0. Orehore on 



It will be convenient to define the ratio E 2 /e by the 

 unknown quantity, p, so that e 2 may be factored out from 

 (17), giving 



F r = t- {-r- 2 + 3 /0 a 2 r- 4 -^ / o(2 f > + l)a 4 r- 6 



electron & L "± 



on electron. ,,- _ - 



. . . (18) 



This equation forms the basis for computing the electro- 

 static force between two coaxial groups of charges, the two 

 atoms of fig. 4. It is to be noted that the force between 

 two electrons does not now follow the inverse square law, 

 but that the forces between elements of their charges do. 



3. The Electrostatic Force upon one H-atom due to another 

 Coaxial H-atom according to the Atomic Model. 



Using (18) as the force between two coaxial electrons 

 instead of considering them to be point charges as in 

 the previous example, it may stand without change as repre- 

 senting the force of the electron A on b, or of B on a in fig. 4, 

 since each distance is equal to r. To find the force between 

 the most distant pair of electrons, A on a, the distance r 

 must be changed to r + 2b. Expanding (r -f 2b)~ 2 , (r + 2b) ~ 4 , 

 etc. and multiplying by the coefficients in (18) gives 



F --= ~{Ar~ 2 + Br- s +Cr-* + I)r- 5 +Er- Q + Fr~ 7 

 Aona ' + Gr-s + H^ + L'- 10 ...}, 



where 

 A=-l; B = 46; C=-12b 2 + 3pa 2 ; D = (32& 2 - 24pa 2 )5 ; 



E= -SQV+l20pa 2 b 2 ~^p(2p + l)a* ; 

 F = 192& 5 -480/>a 2 & 3 + 45/o(2/> 4 l)a'b; 

 G=-448^ 6 +1680 /3 a 2 6 4 -315 / o(2 /3 +l)a^ + g-,o(9p + l)a 6 ; 

 H= 1024,b 7 -^76pa^ + ieS0p(2p + l)a i b"-70p(9p + l)a Q b; 

 I =_23046 8 +16128pa 2 & 6 - 7560p(2p + l)aW 



+ mp(9p + l)a% 2 -°^p(Mp + l)a 8 . . (19) 



The force between the inside pair of electrons, B on b, is 



