Unsymmetrical Components in the Stark Effect. 947 

 From (LI) and (12) we have 



\ 7T / d'2m ehi"7r \ it J 



■ ■ ■ (13) 

 Substituting this value for B 2 in the term involving D on 

 the right-hand side of (7), we have 



B= WA(^ + f) + ^{c- 3 (vC + ^) 2 



3fc*(n 1 + rc 2 + n 3 )N(v'C+— Yl 



+ Fx 4= ^h 



- 32m ^E 2 4/A7r 4 J 



or, substituting the values of D from (5), we have 

 nhi\ — m e ( ( , ~ nAz N 2 



B,^i( V ff + S);5{o-»(^ + ^}F 



F 2 ; . (14) 



+ 4A 



3A 4 (;ix -t- t? 2 + w 3 )N 

 128A 32 7 



writing the two equations embodied in (14) in full and 

 adding, we obtain 



m„*E: v/A(yU+ (wi +^) 



7T 2 ~^ j 



S^[vc + (to^]^. , (15) 



We proceed to solve for A by putting 



TTr , A=-(K + LF + MF 2 ) (16) 



We have 



approximately, 



i— i(-£') » U» 



and 1 i 



A^ = K^ 



3P2 



