﻿Pseudo-Regular Precession . 

 Then if L is the midpoint of OM, 



C 3 M . C 3 = LC 3 2 -LM 2 = LQ /2 , LC 3 = LQ', 

 to determine C 3 . 



Fig. 4. 



187 



MK' = 2MK. 



MC = 2MC. 



L mid-point of OM. 

 LC 3 = LQ'. 



9. Applied about a horizontal axis in the vertical plane 

 GOC, the impulse will make K move horizontally to K 3 , and 

 the axle rise to a cusp at K 2 , C 2 , in fig. 4, if 



C 3 K 3 2 = M 3 K 3 . K 3 D = 2 0M .MK^, 



M 3 K 8 .OC 3 = 20M.MK. 



M,K,_FC, OM 

 MK ~ FC ~ OC 3 ' 



FO, . C 3 0=20M . FC -2GK . KF = G / K' . K'F', 



thence a geometrical construction may be devised for the 

 determination of C 3 and K 3 . 



10. When the impulse is applied in the vertical plane 

 GOC, the impulse vector starts out of the plane, from OK 

 to OH, and K moves to H perpendicular to the plane GOC. 



