Saturation of Salt-Solutions. 

 Table II. 



539 



rc NaCl + 100 H 2 0. 



f 



ft 



r. 



r 

 n 



2 



o 



'5 



8-54 



17-08 





1-0 



17-54 



17-54 





2-0 



3629 



18-14 





3*0 



56-03 



18-68 





4'0 



76-23 



19-06 





5-0 



9742 



19-48 





6*0 



118-84 



19-81 





7-0 



140-92 



2013 





8-0 



163-59 



20*45 





9-0 



186-08 



20-68 





, 10-0 



209-15 



20-92 





10-9 



232-76 



21-16 



"We have therefore: — 



(1) M. V., NaCl solid =27*1. 



(2) Mean M. V., NaCl saturated solution =21*2. 



(3) M. V., NaCl -5 molecule solution = 17'1. 



Now, (1-3) = 10'0, and (l-2) = 5'9 ; and 

 (l-2)^_ 5-9 

 (1-3) 10-0" 



But (2) is the mean volume of each molecule in a saturated 

 solution, when the attraction of similar molecules is equal to 

 that of dissimilar molecules; (3), on the other hand, is when 

 only dissimilar molecules act, and (1) only similar ones. Satu- 

 ration has taken place therefore when the difference between 

 the volume of a molecule of NaCl in the dissolved state and 

 the volume in the solid state has reached '59 of that between 

 the volume in the solid state and that when the molecules are 

 entirely free from one another's attraction. 



Again, in the case of potassium chloride: — 



(1) M. V., KC1 solid =37-4. 



(2) M. V., KC1 in saturated solution = 30'9. 



(3) M. V., KC1 in -5 molecule solution =27*1. 

 (l-2)_ 6-5 §M1 



Here (T^3)--io^ ==63L 



