82 

 Now 



Mr. Meo-h Nad Saha on the 



07T 



(' 



«M 



X^cZIl = — 1 [ — w#v 2 a? + uiu 2 ~\dQtj &c. 



We have now to calculate the value of the integrals 

 \ a^dCl, \a 2 2 dfl, (a^dfl, &c. 



Weh 



ave 



" 1= W (s) = R s ^ fa-®') +w ii (*-*')«^i 



+ (y-yK+(«-«0w 8 +(2-i / )» 4 }]. 



Now let us introduce a Lorentz-transfbrmation by means 

 of which the axis of motion becomes the new time-axis. Let 

 (?> V> ?? *0 denote the new coordinates. We have then 



= "A n A M A,, A 14 ^ 

 9?') I A„ A 



(f-r)l 



0?-V) 



(v-v-) 



V) J 



x 2 2 A 23 A 24 



A 31 ^32 -a-33 

 ,A« 



L 3 4 



A 42 A 43 A 44 j 



.17 — £ 



y-y 



l-V 



wher 



and 



A^ + A^ + A^ + A^l, 



A lh A lk + A 2Jk A 2 * + A 3h A 3 /, + A 4 * A ik = 

 Since the line of motion is the new time-axis, we have 



we have therefore 



A 41 = ?'?#!, A 4S = it& 8 , A 4 3 = ZZ0 3 , A 44 = 220 4 . 



Now using the above transformation, we have 



B 2 =(f-r) 2 +(';-v) 2 +(?-r) 2 



