Resistance, and Self- Capacity of Magneto Windings. 61 



total electrostatic energy would have been 5'9 x 10~ 3 joule, 

 and the peak voltage 14,600 volts. Thus the effect of the 

 energy loss in the primary and secondary windings is to 

 reduce the peak voltage 32 per cent. 



(8) Second method of calculating Energy Loss. 



(a) The energy loss in a magneto can be approached from 

 a different point o£ view using the formulae given by Taylor- 

 Jones *. He has shown that when (1) there is no loss in the 

 primary and secondary circuits (the whole of the energy in 

 the primary would not necessarily be transformed into the 

 spark in the secondary if there were no loss), (2) the two sets 

 of oscillations which occur after break are damped sine waves, 

 and (3) the interruption of the primary circuit is perfect, the 

 peak voltage is given by the expression 



L^+L.2! - Usi , (9) 



VL.A v w 



Taking L e2 i = ~M. = k \/L e iL e2 , this expression can be written 



Tr r L ei , , ;T~ 7 ~\ U sin <b 



v 2 = — t=+* VL el r per ampere 



L V -U2 -1 V C 2 



broken in the primary circuit. . (10) 



U is given by the expression 



1 



[u + s-2{(l-k 2 )u}^ 



(11) 



where u = — ~ . 



J e2^2 



2tt 



</> is given by -. , -, where n 2 and /i 2 are the frequencies 



o£ the two oscillations, and n 2 /n x lies between 1 and 5. If 

 n 2 /fti is greate/ than 5, the expression for c/> is found by 

 multiplying by some power of 2. 



The ratio n 2 \n x is obtained from the relation 



(n2\ 2 = * + ?*+[(* + ^ 2 -4(l -/■>]_* 

 * Phil, Mag. vol. xxxyi. Aug-. 101 S. 



