468 Mr. F. J. W. Whipple on the Motion of a 



width we determine the points at which the motion is north 

 or south by solving the equation (8'22) 

 d<j> 



df 



= ft>V[sech 2 f-i]=0. 

 Fig. 3.; 



1000 



5 500 



0° Q 



CASE-ICi 



EQUATOR CROSSED AT 150! PERI0D=£03 hours. WAVE LENGTH 1,630 km. 



I0m/s /^"\ RETROGRADE MOTION IN- 



10N6ITUPL 



iooq> 



1500 



CASE ff. 



■ASYMPTOTIC APPROACH TO EQUATOR. WIDTH OF LOOP 704 KM 

 . JQ . LATITUDE l!-3° X^X TIME ROUND LOOP = 70 hours: 



- J00Q 



§ 50Q 







ZQ- CASE I II a. 



^000 APPROXIMATELY CIRCULAR PATH WITH DRIFT TO .WEST 150km. EACH REVOLUTION. 

 LATITUDE 16-85° ^ / , K - 



U5QO 



, ^ iLTITUDE &•$ 



^JOOO: 



*J'DTH- OF LOOP 48M. LAND W„ FROM N. CURRENT TO & 

 632 KM. FROM S. CURRENT 10 N, 

 5 B 500/ ^ ANGE N -- AND S - 550KM. 



