344= Mr. A. A. Michelson on the Application of 



This gives 



v __ sin irn _ 1 



irn 1— n 2 ' 

 or 



-y _ sin7rn on 2 



irn mr—n* 

 which agrees with IV. 



ix. #W=i+"J, #M=i-£ 



O<0), O>0). 



Putting 27rD = &, we have 



C= F^ 1_ C0S ^ + F/( 1_cos ^> 



S= ^ sin ^""F/ sin ^ 

 p=i(*+/). 



If, now, ke 



¥ 



and 



LIT 



we have 



V2 _ l—rg cos 2tt7 , 1 7i— 7*1 cos 27rr 2 n — 2r l r. 2 sin 2 7ni 



y= *.. 



/7rn\ 2 



W 



If/=0, g=«, and 



k 2 G = — (1 — cos ka), 



PS= — (sin &a— &a); 

 a 



whence 



V2 _ 1 r\ sin 2 7rn _ sin 27rn~| 



" 7T 2 7£ 2 L W S tt 2 27T71 J ' 



In the case of an unsymmetrical source, it is possible to 



