442 Mr. J. H. Jeans on the 



parallel to the axis of the molecule. We must in this case 

 write 



L = Hip r w sin 2 0, 



M = Hip r w sin 6 cos 6, 



N = - Hip {rv cos 6 + u sin 6) . 



Writing E for pEj + o^ (§ 13) and 



SE/Br for pdEJdr + adEi/dr, 



the equations of motion will be (cf. equations 8, 9, 10, 

 p. 432) 



cjpHi— j- +^W — pKipriu sin 2 #, . . . (26) 



/7F 1 

 a-p <2 r' 2 v= -y- — pHipr^io sin 6 cos 6, . . . (27) 



<rp*r* sin 2 6w= — + pRip r sin (r« cos 6 + w sin 0) . . (28) 



We shall only attempt the solution upon the supposition 

 that H 2 may be neglected, and in this case we obtain from 

 (26) and (28) 



2 8E , w pH.vpd'E 



<rp 2 u= ir - +uW — ^— -£- — 



or o-pV a 9 



Equating the various harmonics in this, we obtain (cf. equa- 

 tion 11, p. 432) 



y2 a « = S^+^W + — J" • • • (29) 

 6Y op* 



Similarly we obtain from (27) and (28), 



r dd orp z d(j)' 



Equating coefficients of e™® , multiplying by sin 0, and 

 operating with ^^^g, we get 



apV2/3™ F»( M ) = ( — * (sin e^l^l ) 

 From (28), with the help of (26) and (27), 



