R? 
647? 
652 Mr GW Walker ov 
As an integral of these we readily obtain 
(74, + Ne) CRX =e, ts... neve 4 
where 7 is a constant and is the current through the gas per 
unit area. 
We also get 
(seat) 
it 2B( ie = xa \nita= OX. ree 
where C is a constant. 
Putting X?=y and eliminating 7, and v2, we get 
pic 
Be PO We Ose —geR 2CeR | Sxem 
sil) =i? +- — gs yl 
a 
saa ve gate) wi 87eR 
oS = =0 at v=0; so that if y=Yo at 
z=0 we get 
. 2Ce?R S7eR eR 
i Sa Yo ca Z a . Y o> (7) 
Sek. ae (1 =x) 
and 
SaeR ~~ 8areR 
lied iat o> Ree ( sre 
ae Ly pi " Yo) fragt) y " yo 
By giving Sar a suitable values, (8) can be integrated 
without much difficulty. I selected: as =2 as the easiest. 
If the laws hold so far this would correspond to ordinary air 
at 8 atmospheres pressure, so that the case could be obtained 
experimentally. 
It is unnecessary to suppose that n,n, vanishes at the 
plates. Various circumstances might prevent this, such as 
a small supply of ions from the plates themselves, or the 
presence of a thin layer of radioactive material. We shall 
therefore suppose that, at «= +1, 
6d a 
NyNy= coon pres 9 (ny). 
