Mr. J. Parker on Thermoelectric Phenomena, 355 



(2) Disconnect the metals A, B, and then raise the tempera- 

 ture to t -f dt. The heat absorbed will be 



By slowly moving the plates A and B, let the potentials be 

 altered to V/, V/, where 



d8 



dt 



Yp'-Y a '=8+™.dt. 



The work done on the system will be 



j(B.- 2 )(T.'-V.)+i(E ( ,+ 2 )(V/-V (J ). 



(3) Connect the plates A and B again, and let q return 

 from B to A without altering the potential of either. 



The heat absorbed = — (tl-\-dTl)q, and the work done on 

 the system = ^q(8 + d8). 



(4) Let the plates A, B, be again disconnected, and then 

 reduce the temperature to t. The heat absorbed will be 



-(Ma+M^)*-E. .&«ft-E, .4fe«ft. 



Lastly, bring the potentials back to their original values Va, 

 Vp. The work done on the system 



The total work done in operations (2) and (4) = %q.d8. 

 Hence, from the complete cycle, we have, by the principle of 

 equivalence, 



« -I (/-/«) » 



Also, by Clausius* principle, 



n n+dii 



t t + dt 

 i. e. 



d( 

 dt . 



+7(«-#)*=°. 



("H i </«-/•» » 



