DEGREE 
og. @* »  , 7.0476694 
Sine 1” . 4.6855749 
Sin? Z - 9-G9139-0 
Tang. L’ - 0.0875019 
Loy. 0.5 - 9 6 j8y7-0 
Cor, 32.44 Lg f1t102 
469".93 — 32/44 = 435) oe = 2,6389732 
@ col”? L - 73845326 
Cor 1.165 = G.Ol35 105 
Difference oF “Yatie We = i So As = 430.6. 
To find Z’ or azimuth « f Dunnofe,. as feen from Beachy- 
hea 
Tl wx 180. + Z iin. Z. tang. ie f° Be @, fin.? Z. 
. 3.52 38228 Log. 9 39794 
Sin. Z 9+9956979 -0476 
Tang. L’ 0.087 6046 Sra Yn 4.9855 
Sir.’ Z 9244351 
4046.9 = 3.6071244 
eieaerageneree — 3.75 so a 
4046".9 — 3-7 = 4043/2 = 1° 
If Z = 98° 3! 7% — Z’ = 96° 55’ 43.3, err is 
nee lefs than the obferved azimut:.. See Trigon. 
Surv 
IF . e fappofe the obferved azimuth to be correct, namely, 
96° §5/ 58%, it would follow, that we have made an es 
neous fuppofition of the value of the norm mal. The 
r @ fin. Z, tang. L’ is equal t to 4032.7 lesae 
seis. on 3 hence log. o> = 345222943. 
, = K Rv 
ay ao ee Q 
- = §.5307092% 
RY = = 4543144251 
Co. log. @ = 664777057 
Log. - == 73228400 
= 7581226 
3600 = 1075 122 
— Feet. Fathoms.. 
5-5647174 = 3670 
length of a ee perpendicular to the meri 
A difference of 5” in the value of Z’ wiil aa uce an error 
of 47 Eioay in the Jength of the Spenco degree. 
Example V 
Given AB=K= nly 4 
Z= al S30". 
L= os 8 = Lat. of A. 
Required the diftance cee the parallels of A and B, 
Dunnofe and Butfer-hill. 
Log. K = 5.1479235 
R’ x co. log. norm. = 7.9934145 
3.1410380 = 23’ 3”.6 
ZO=11 31.8 
Cof. 59 - = 9-.9999982 
SF 51419735 
Cof. Z - = 9.9702169 
231259 = 5-1 181 386 
Sorters sae A 
La : © == 7.5256826 
eg ' = 9:5 538847 
ang. - = 9.5336737 
Tang. i = =o o8e7326 
6 7489735 
one delat 
If. - - 79 Oi 1; 1.867104 aad 
Sin £0 = == 75256801 
"Tang. 59 “ =752 26826 
Sin? L - = 9.7703016 
Tang? L - 20,1 Ue td 
4-99912093 
Log. 2 - = 0.3010300 
Log. K§@cof.Z 5. 1181306 
II. - - 2.619 = 04182899 
Log. g. firft terms =o sooty 
= 5.3558 46 
= 
= 5.3594627 
x 3 
Co log. 6 
Co log. Rad? 
0.86 = 9.9371576 
I. - = 3131259 
If. - —_ 73.6 
Ill. - + 2.62 
_ LV. - + 0.86: 
131188.9 
Example VI. 
To find the difference between the parallels of Beachy- 
head and Durnofe. 
I. (Keof. £9 cof.Z). 
II. 4- (Keof. eats Z)tang. 19 fin. Z tang. Z tang. L.. 
Ill. — a i £dcol, Z) crm) tang. 3 fin.” Ltang.?L. 
f 3° firft t 
IV. + sate 
Log. $= 3.5238228 = 3940.6= 55740" 6 = K R” 
59=27 50.3 norme. 
K m 
Cof. Z - 
Cof,iQ@ +. 
= 55307092 
= 9-1463479 
= 9.9999858. 
T= =) 47538-3=4-9770429 
Tang. 4 : == 79043008 
Sin. Z =9 9956970 
Tang. Z = =0.8493490 
Tang. L = =0.0877597 
8.8411065: 
Log. (K. cof. $9 cof.Z) =4.6770429 
II» « $f 3297.2 = 3.5181494 
$in. 
