Intelligence and Miscellaneous Articles. 



563 



manner represents the negative ion. Prom this may be calculated 

 the transfer-number and the conductivity. If, further, A is that 

 quantity of hydrogen which is liberated in a second by a current 

 of unit strength in electromagnetic measure, the molecular con- 

 ductivity, L, expressed in electrochemical equivalents, is 



A \upUp \x n u n f 



lip 



If U and V are the absolute mobilities of the ions, then L =U+ V, 

 and therefore 



IP ^ lr 



u= 



Kiip tip ' 



Y = 



Afx n u ri 



With the aid of the values of U and V given by Prof. Kohlrausch 

 the author thus calculates : — • 



Positive Ions. 





H. 



Li. 



NH 4 . 



Na. 



K. 



Ag. 



U10 13 



300 

 1 

 0-82 



22-6 



7 

 0-16 



51 

 18 

 0-59 



33-5 

 23 

 0-44 



52 

 39 

 0-89 



43 



107-7 

 1-22 



1 P 10 8 





Negative Ions. 





F. 



CIS. 



CI. 



C 2 H 3 2 . 



N0 3 . 



Br. 



C10 3 . 



I. 



y io 13 



32-4 



19 



0-12 



54 



26 

 0-75 



53 

 35*4 



0-86 



24-8 

 59 

 052 



496 

 62 

 1-07 



572 



79-8 

 1-39 



43 



83-4 

 1-07 



57'2 



126-5 



1-76 



z„io 



Por the coefficient of diffusion of an electrolyte, finally, that is 

 the number of gramme-molecules which with unit difference of 

 concentration pass through unit section, the author finds 



&=40-l(l + 0-00367*>Ux 10 10 , 



in which n is the transfer-number, and TJ the absolute mobility of 

 the ion in question. Thus for hydrochloric acid, n— 0*19 and 

 17=300 xl0~ 13 , and therefore &=2-44. Observation gives 2-30. 

 This example also proves the agreement between Biecke's equation 

 and that which Nernst first gave for the connexion between the 



