
Structure of the Atom. FD 
cutting the curve in Q, draw the ordinate QM; then the 
integral part of QM will be the value of n,, the number of 
Fie. 1. 

6 Mz 20 MP 40. MR 60 P 30 00 
corpuscles in the first ring reckoned from the outside. For 
evidently 
OM =/(QM), 
and OM=ON—NM, and since PQ is inclined at 45° to the 
axis, NM=OM;; hence 3 
ON—QM=/(QM). 
Comparing this with equation (1) we see that the integral 
part of QM is the value of n. 
To get the value of n,, the number of corpuscles in the 
second ring, we mark off the abscissa OP; =N—n, (if QM is 
an integer P, will coincide with M), then from P, draw 
P,Q, parallel to PQ cutting the curve in Q,; the integral 
part of Q,M, will be the value of n,. To get n; mark off the 
abscissa OP,=N—n,—7, and draw P,Q, parallel to PQ; the 
integral part of Q,M, will be the value of n;. In this way we 
can in a very short time find the configuration. 
The following table, which gives the way in which various 
numbers of corpuscles group themselves, has been calculated 
in this way; the numbers range downwards from 60 at 
intervals of 5. 



























Number of corpuscles ......... 60. DD. 50. 45. | 40. 30. | 
Number in successive rings ae, 19 18 17 16 16 
b aged tls iene ft ie iene 
3 12 }1 10 8 65 
5D 7 ) SUN eas 1 
| 3 1 1 
| Number of corpuscles ......... | 380. | 26. 20. 15.0 el a. | 
| Number in successive rings...) 15 13 12 1 ime 5 | 
10 5 7 5) 2 
| 5b 1 | | 


