of a Spherical Mass of Gas. 

 Taking c = 15 X 111 x 13 1 ' 4 x 32'2, 



163 



which is the value, in foot pound units, of -^ in our atmo- 

 sphere at the surface of the earth ; and taking also 



1 



we get that 



K = 



^3xllP 



= - x 25'5 x 10 G feet. 



x 1820 miles. 















ZT 



j 



















y-AX/s 















i ! 









































































































50 



















/ 























































































































/ 



















































































1 































When p is zero r=l\)0 miles, and when r is zero 

 p = 100,000. This, however, does not correspond to any 

 physical conditions, for the density of a gas cannot have such 

 a large value. I shall now show, however, how the solution 

 can be adapted to give any arbitrary value of p at the centre. 



If we put 



and 



1 / e~^~ 



•K( 7 -l) 

 in equation (5), p and q being constants, we get 



P'l 





dx< 



r m r*> 



and if we makep l ' 5 q 2 = l, this reduces to equation (7) whose 



