Carbon Compounds in Concentrated Solutions. 



217 



Loss of alcohol tube 2=4 - 988 grms.; loss of tube 2 corresponding to p = - 960grm. 

 " 1=4-700 " " " 1 = 0-915 grm. 



" tube 1 corrected = (4-988/4'700) 0-915 corresponding to p' =0-971 " 



P~P 



0-011 



11 



Error = --.- 100 = l'l per cent. 



A second experiment gave an error of 1 per cent, so that 

 the mean error would be 1*05 per cent of the quantity meas- 

 ured. The temperature in this case was 41*3°. In this way, 

 the errors given in the following table were determined. The 

 first column gives the solvent, the second column gives the 

 corrected value of either L t or L 2 as the case may be, the third 

 column gives the difference between the observed maximum 

 L and the corrected L. When — , the corrected value is 

 greater than the observed value. The fourth column gives 

 the percentage error and the fifth column the mean percentage 

 error. The sixth column gives the temperature. 









Per cent 



Mean per 



Substance. L 



AL 



error. 



cent erroi 



. t° 



Water 



L x = 1-022 



— 0-010 



1-0 





41-2 



tt 



L x = 0-971 



-o-oii 



1-1 



1-0 



41-3 



a 



L 2 = 0-597 



+ 0-002 



0-3 





32-3 



a 



L = 0-591 



+ 0-004 



0-7 



0-5 



32-3 



Methyl alcohol L; = 4-044 



+ 0-068 



1-7 





44-0 



U i 



' L 3 = -5-220 



+ 0-038 



0-7 





44-0 



ii i 



' L x = 6-266 



+ 0-039 



0-6 





44-0 



ii i 



L a = 5-146 



+ 0-048 



0-9 



1-0 



43-8 



ii I 



L x = 3-159 



— 0-013 



0-4 





31-4 



ii I 



L 2 = 3-360 



+ 0-019 



0-6 



0-5 



32*2 



Ethyl 



L 2 = 6-814 



— 0-112 



1-6 





44-8 



a i 



L x = 5-441 



— 0-033 



0-6 



1-1 



44-8 



a i 



L 2 = 2-880 



— 0-056 



1-3 





26-9 



a i 



L, = 2022 



— 0-005 



0-2 



0-75 



26'9 



Propyl ' 



L x = 1-134 



+ 0-012 



1-1 



1-1 



31-3 



a i 



L x = 2-663 



— 0-015 



0-6 





45*2 



a i 



' Lj = 2-254 



— 0-023 



10 



0-8 



45-2 



Toluene 



L 1 =• 1-356 



+ 0-003 



0-2 





27-5 



a 



L 1 = 1-384 



— 0-005 



0-4 



0-3 



27-5 



a 



L x = 4-700 



+ 0-051 



1-1 





45-1 



u 



L = 4669 



+ 0-028 



0-6 



0-8 



45-2 



These errors do not represent the total errors of the appa- 

 ratus because in their determinations, so far as conditions will 

 permit, the air is completely saturated with solvent vapor. 

 But in measurements of the relative depression of the vapor 

 pressure tube 1 contains more or less concentrated solutions 

 and therefore one current is not at maximum saturation and 

 the conditions are not the same as they were when the above 



