﻿262 
  A. 
  M. 
  Mayer— 
  On 
  the 
  Flotation 
  of 
  

  

  would 
  be 
  at 
  R, 
  in 
  the 
  horizontal 
  plane 
  of 
  the 
  disk 
  ; 
  but 
  it 
  was 
  

   found 
  to 
  be 
  at 
  R/, 
  so 
  that 
  EsE' 
  equalled 
  6°, 
  thus 
  giving 
  6° 
  

   for 
  the 
  angle 
  at 
  s 
  of 
  the 
  water-surface 
  with 
  a 
  vertical 
  to 
  that 
  

   point. 
  Call 
  this 
  angle 
  d. 
  

  

  We 
  are 
  now 
  in 
  possession 
  of 
  the 
  facts 
  pertaining 
  to 
  the 
  forces 
  

   acting 
  on 
  the 
  floating 
  disk. 
  W 
  and 
  P 
  are 
  known 
  and 
  T=W 
  

  

  T 
  

  

  —P. 
  If 
  the 
  equation 
  W=P 
  + 
  T 
  be 
  correct, 
  then 
  ~ 
  cos 
  a 
  

  

  circ 
  

  

  should 
  equal, 
  or 
  approximate, 
  the 
  value 
  of 
  A, 
  the 
  capillary 
  

  

  constant, 
  or, 
  the 
  surface-tension. 
  

  

  Data 
  relating 
  to 
  disk 
  No. 
  1, 
  and 
  value 
  obtained 
  for 
  A. 
  

  

  Diameter 
  of 
  disk 
  5'09 
  cm 
  

  

  Thickness 
  of 
  disk 
  _ 
  -l 
  cm 
  

  

  Circumference 
  of 
  disk. 
  _ 
  15'99 
  cm 
  

  

  Area 
  of 
  disk 
  20'348 
  Sf 
  i 
  cm 
  

  

  Density 
  of 
  water 
  at 
  18° 
  '9986 
  

  

  W 
  .- 
  ll'313& 
  rhms 
  

  

  h 
  -497 
  

  

  P 
  = 
  aM=20-348X 
  "497 
  X 
  -9986 
  = 
  10-092 
  

  

  . 
  W 
  — 
  P 
  nQ 
  11-313 
  — 
  10-092 
  __ 
  nHnHn 
  

  

  A 
  = 
  — 
  : 
  =- 
  cos 
  6° 
  = 
  — 
  — 
  4- 
  -9945 
  = 
  -07678 
  

  

  circ 
  15*99 
  

  

  For 
  disks 
  No. 
  2 
  and 
  No. 
  3 
  W 
  and 
  h 
  were 
  determined 
  by 
  

  

  series 
  of 
  measures 
  similar 
  to 
  those 
  make 
  on 
  disk 
  No. 
  1. 
  The 
  

  

  departure 
  of 
  the 
  minimum 
  and 
  maximum 
  measures 
  from 
  . 
  

  

  the 
  mean 
  was 
  about 
  the 
  same 
  as 
  obtained 
  in 
  the 
  measures 
  on 
  

  

  disk 
  No. 
  1. 
  

  

  Data 
  relating 
  to 
  disk 
  No. 
  2, 
  and 
  value 
  obtained 
  for 
  A. 
  

  

  Diameter 
  of 
  disk 
  4*975 
  cm 
  

  

  Thickness 
  of 
  disk 
  -l 
  cm 
  

  

  Circumference 
  of 
  disk 
  15-63 
  

  

  Area 
  of 
  disk 
  19-438 
  sc 
  i 
  cm 
  

  

  Density 
  of 
  water 
  at 
  1 
  8° 
  -9986 
  

  

  W 
  - 
  - 
  10-885S 
  ram 
  

  

  h 
  -495 
  cm 
  

  

  P=«M= 
  19-438 
  X 
  "495 
  X 
  -9986=9'608 
  

  

  W-P 
  n0 
  10-885 
  — 
  9-608 
  _' 
  

  

  A= 
  — 
  : 
  --cos 
  6°= 
  '-•9945 
  = 
  -08215. 
  

  

  circ 
  15-63 
  

  

  Data 
  relating 
  to 
  disk 
  No. 
  3, 
  and 
  value 
  obtained 
  for 
  A. 
  

  

  Diameter 
  of 
  disk 
  5'57l 
  cm 
  

  

  Thickness 
  of 
  disk 
  -l 
  cm 
  

  

  Circumstance 
  of 
  disk 
  17-<5 
  cms 
  

  

  Area 
  of 
  disk 
  24*38 
  8< 
  i 
  cm 
  

  

  Density 
  of 
  water 
  at 
  18°.. 
  -9986 
  

  

  W 
  13-739 
  

  

  h 
  -508 
  

  

  P=aXAxrf=24-38X'508X 
  '9986= 
  12-368 
  

  

  A 
  W 
  — 
  P 
  13-739—12-368 
  K 
  ww 
  

  

  A 
  = 
  -, 
  --cos 
  6°= 
  ^--9945 
  = 
  -07877 
  

  

  cue 
  17*5 
  

  

  