286 Linhart — Hydrolysis of Alkyl Metallic Sulphates. 



Table I. 



T = 55 c 



= 20 cm3 of normal NaOH 





BaS0 4 







t 



in 





K* 



Kf 



Kt 



in 



in cm 3 



minutes 



grams 



0-1 mol 







10020 



0-146 



6-3 21-4X10" 6 



20-2 XI 0" 6 



20-5 XI 0- 8 



20340 



0-249 



10-7 20-0X10" 6 



17-6 X10- 6 



18-0 X10- 8 



00 



0-744 



S2'6 = a 













b =.- 20 cm3 of 0-5 normal NaOH § 



10020 



0-062 



2'7 8-5 X10 -6 



8-42 X10- 6 



17-1 X10- 8 



20340 



0-110 



4-7 7-6 X10~ 6 



7*36 X10- 6 



15-0 X10~ 8 



29040 



0-163 



7-0 8-3 X10- 6 



7-82X10" 6 



16-2 X10- 8 



39120 



0-210 



9-0 8-3 X10- 6 



7-59 X10" 6 



16-2 X10- 8 



00 



0-744 



32-6 = « 



Table II. 







t 



in 

 minutes 



600 



1440 



8310 



10690 



oo 



BaS0 4 



m 



grams 



0-032 

 0-074 

 0-319 

 0-371 

 0-744 



m cm 

 0*1 mol 



1-4 



3-2 



13-7 



15-9 



S2'6 — a 



T = 



K 



20 cm3 of normal NaOH 



74X10- 6 

 72X10- 6 

 66X10- 6 

 60X10" 6 



Kf 



73-7 X10- 6 

 69*9 X10~ 6 

 56-6 X10~ 6 

 52-4 X10- 2 



KJ 



72-1X10" 

 70-0 x 10" 

 58-6X10" 

 54-4X10" 



From theoretical considerations, as already pointed out, it 

 might be supposed that the discrepancies inKremann's constants, 

 especially those in Table II, are due to the fact that he used 

 sodium hydroxide for the saponification of the ethyl barium 

 sulphate. In order, therefore, to avoid these difficulties, the 

 several esters treated of in this article were saponified in hydrox- 

 ides whose metallic element was either the same as, or simi- 

 lar to, the one contained in the ester. The reaction taking 

 place under these conditions may be represented by the gen- 

 eral equation : 



* K = -?£ log - 

 t a 



x 

 2-3x2 



f K = 2x23 log 



a — \x 



+ (a - b)t & (6 - \x)a 



| 20 cm 3 of normal NaOH -=100 cm 3 of 0'2 normal NaOH. 

 § 20 cm 5 of 0-5 normal NaOH =£= 50 cm 3 of 0*2 normal NaOH. 



