**4 A MEW ™ d VNIFERSAL SOLUTION 



i. To compute^, the firft term in the feries, approximating 

 to BC : Since e zz e zz l, we have 



tan A r: fee. 45 ° zzi 10. 1505 150, 

 therefore A 5= 54 44'. 



A 



Then fin x =r tan — X fin 45 ; and /> 5= 90 ° — 2X. 



A 



Now log. tan — =: 9.7140051 

 log. fin 45 = 9.8494850 



log. fin x r= 9.5634901 n fin 21 ° 28'. 

 Therefore X = 2 1 ° 2 8", and /> = 90 ° — 2 X = 47 ° 4' j this value of 



p is lefs than BC. 



r m — p 

 fin 1- 



2. To compute the fecond term p' } we have e zz s x 



fin 21 28' %' A _ w r . fin 21*28' 



~ ^ — ^, and tan A — e X fee 45* = — — r v fee 4< . 



arc2i°28 arc 21*28 * ** 



log. fee 45 = 10.1505150, 

 log. fin 21° 28'= 9-5634335 



fum — 10= 9.7139485 

 add conftant log. = 3.5362739 



13.2502224 

 fubtract log. 1288' (= 21 * 28*) = 3-1099159 



log. tan A = io.1403065 

 therefore A = 54* 5' 54". 



Then, 



