Of KEPLER'S PROBLEM, 227 



log.co£<p= 9.4805383: 

 log.cof^—— - = 9.9974523 



2 



I9.4779908 



log. cof rJXJL — 9.6058923 



log. cof ip rr 9.8720985 

 therefore ^ =. 41 ° 51', 

 confequently p =. <p — ^ =z $0° 33', which is lefs than BH. 



fm^J=i > 



2. For the next term p\ we have e = s X — 



~{m—p) 



fin m 



fi£?.4i«; 3?;. ^ +(!-,)* = 



arc 14 43 3° * ' 



log. fin 14 43' 30" - 9.4051412 

 add conft. log. h. 3.5362739 



fum — 10 = 2. 941 41 5 1 

 fubtrad log. 883'. 5 = 2.9462066 



log. e — 1.9952085 



log. - = 0.0047915 



2 



log. - — 0.0095830, and 1 =: 1.622410, 

 alfo - — 1 = .022410 = a. Now, log. fin m = 9*9375306, 



therefore log. — y- = 9-947 IJ 3 6 » and —r — -885347 = &• 



The 



