340 



NEW SERIES for the 



Example II. The length of an arch of 90°, computed by 

 the fecond feries, (Art. 22.). 



cof a 3= o eof-rV^ = 0.99518472667. . 



cof 7 a hz 0.70710678 1 1 865 cof T ' T tf — 0.99879545621.. 



cof-^d ■=. 0.9238795325113 . cof 7 ' ? <?r 0.9996988187 ... 

 cof i a — 0.980785280403 . 



Amount of pofitive 1 1 + cof a , 1 __ _5 

 terms, 4 1 — cofa 8 " ' 12 



12 



1 1 — cof \ a 

 4* 1 + cof 7 a 



I t — cof 7 a 

 4* 1 + cof 7 a 



x 1 — cof^a 

 4 4 1 -+" cof \ a 



I 1 — cof -V a 

 4? 1 -j- cof -V « 



JL 1 — cof T ' 7 a 

 4 6 1 -f-cof T ' T tf 



II — cof F * 7 a 



z: .416 666 666 666 7 



=- .0107233047034 



— .000 618 220 7796 

 r= .000 037 892 799 o 

 = .000002 356 882 2 

 = .000 000 147 127 6 



- =: .000 000 000 192 7 

 47 i + cof T ' T « y * ' 



S < .000 000 000 612 87 j _ ^ 



/ Hence S = .000 000 000 612 7 



S> .000 000 000 612 6j 



Amount of negative terms, .011 381 932 097 2 

 Difference between the pofitive ? Qr j. _ .4053847345695 



and negative terms, 



1 

 a 



1.6366197723677 



Arch of 90 , or a ss 1.57 79 6 3 26 795 • 



Example 



