
STRESSES DUE TO COMPOUND STRAINS. 491 
terms of J, H, and K,. To do this we must first arrange K, according to the 
terms which are of the first, second, third degrees, in terms of the secondary 
strains, as follows:— 
K,=K,+(h+hJ+9+Gtg—tH+sK. . . (84) 
Mie stress S2, is /given by V,Se:= ae where, after differentiation, the 
secondary strains are to be put equal to zero. When, therefore, we write 
dW, (dW) dd, Cane ef ae dK, 
Wk Nae), ga ao dK), dA” 
we need only attend to those terms in H, and K,, which are linear in 
eer... 
Substituting for J,, H, and K, we find 
vostu=a{ (a+ ae rea fe (Gr) 2Ge),* ne +9[ Ga), + (GR), |(e-a. 
If we write this result, 
S.x=L+ Ma+N(be—d’) , 
the type of the tangential stresses is 
=M/+ Nde—¢f ), 
