138 



Artur Rosenthal, 



[96] 



Die allophänen Typen ergeben sich unmittelbar durch Spezialisierung 

 aus den allgemeinen Zusammenstellungen (s. S.85ff.); fast einfacher ist es jedoch, 

 nach den früher angegebenen Methoden die allophänen Typen neu abzuleiten. 



Die Aufsenfläche wird von einer einzigen Zellform gebildet. 



Nr. 



Zellformen der 

 Aufsenfläche 



Verdeckte Zellformen 



Anzahl 



der isophUnen 



Körper 





a) 



(1 = 7) 











2« = 1 



0^ 



b) 



(2 = 8) 





(1 = 7) 





2' = 2 



O 



c) 



(3 — 9) 





(1 = 7) 





21 = 2 



'o 



d) 



(4 = 10) 





(1 = 7), (2 = 8), (3 = 9) 





23 = 8 





e) 



(11 == 14) 





(1 = 7), (2 = 8) 





22 = 4 



N 

 g 



f) 



(12 = 15) 





(1 = 7), (2 = 8), (11 = 14) 





23 = 8 



in 



g) 



(5 = 18) 





(1 = 7), (2 = 8), (3 = 9) 





23 = 8 



§ 



li) 



i) 



(6 = 20) 

 (13 = 30) 



(1 = 

 (1 = 



= 7), (2 = 8), (3 = 9), (4 = 10), (5 ^ 

 = 7), (2 = 8), (3 = 9), (5 = 18), (11 = 



18) 



:=14) 



2^ = 32 

 25 = 32 



halb 

 gesohlü 



Gesamtssahl der hierhergehörigen Polyeder: 25 (+ 72) = 97. 



IL 





Die Aufsenfläche wird von zwei Zellformen gebildet. 





Nr. 



Zellformen der 

 Aufsenfläche 



Verdeckte Zellformen 



Anzahl der 



isophänen 



Körper 





a) 



(2 = 8), (3 = 9) 



(1 = 7) 



21 = 2 



a 



b) 



(3 = 9), (11 = 14) 



(1 = 7), (2 = 8) 



22 = 4 



Ol 



o 



c) 



(3 = 9), (12 = 15) 



(1 = 7), (2 = 8), (11 = 14) 



23 = 8 





d) 



(4 = 10), (11 = 14) 



(1 = 7), (2 = 8), (3 = 9) 



23 = 8 





e) 



(4 = 10), (12 = 15) 



(1 = 7), (2 = 8), (3 = 9), (11 = 14) 



21 = 16 



a 

 bc 



f) 



(4 = 10), (5 = 18) 



(1 = 7), (2 = 8), (3 = 9) 



23 = 8 





g) 



(4 = 10), (13 = .30) 



(1 = 7), (2 = 8), (3 = 9), (5 = 18), (11 = 14) 



2=" = 32 



a 



h) 



(5 = 18), (11 = 14) 



(1 = 7), (2 = 8), (3 = 9) 



23 = 8 



o 



i) 



(5 = 18), (12 = 15) 



(1 = 7), (2 = 8), (3 = 9), (11 = 14) 



21 = 16 



i 



k) 



(6 = 20), (11 = 14) 



(1 = 7), (2 = 8), (3 = 9), (4 = 10), (5 = 18) 



25 = 32 





1) 



(6 = 20), (12 = 15) 



(1 = 7), (2 = 8), (3 = 9), (4 = 10), (5 = 18), (11 = 14) 



2" = 64 



'rt 



m) 



(6 = 20), (13 = 30) 



(1 = 7), (2 = 8), (3 = 9), (4 = 10), (5 =18), (11 = 14) 



26 = 64 





n) 



(12 = 15), (13 = 30) 



(1 = 7), (2 = 8), (3 = 9), (5 = 18), (11 = 14) 



25 = 32 





Gesamtzahl der hierhergehörigen Polyeder: 38 (+ 256) = 294. 



