PROFESSOR LETTS ON PHOSPHORUS-BETAINES.  . 307 
The equation, 
CH,— COOH CH,—CO 
gua eter 
= (CHP +H, 
requires a loss of 9°27. 
The compound which had thus been dried was then burnt with oxide of 
copper and chromate of lead, taking the greatest possible care to introduce it 
into the combustion tube in the dry state, a task of some difficulty, owing to its 
strong attraction for moisture. 
04160 gave 03715 H,O = 0:0413 H = 9°8 per cent. H 
= C 
04160 ,, 08380 CO, = 0:2285 C= 549 ,, 
Hy 
Obtained, Calculated for (C, ch lh 0 oe 
Carbon, . 049 : ; ; ‘ ; 54°6 
Hydrogen, .« 9°38 ‘ ‘ . ; . 9-6 
Now this result is of some importance, as the base thetine has been shown 
to behave in exactly the same manner; that is to say, when dried over sulphuric 
acid, it has the composition of a hydrate, but im vacuo it loses a molecule of 
water. Thus— 
CH, — COOH PEs 00 . 
=(CH)SC wy, +H,0 
(CHSC 
And not only in this respect do the two bases resemble each other, for in 
their other properties they are closely analogous. Both are highly deliquescent ; 
both crystallise in the same manner, but only when their solutions are highly 
concentrated ; both have a neutral reaction ; and as will be shown presently, 
both behave in a similar manner when heated. 
Sulphate of Triethyl-Phosphorus-Betaine.—This compound was prepared 
by adding sulphate of silver to a solution of the hydrochlorate, filtering from 
chloride of silver, removing dissolved sulphate of silver by means of hydrochloric 
acid, and after filtering the solution evaporating it im vacuo over sulphuric 
acid. After a considerable time the syrupy liquid which remained, when 
most of the water had evaporate, solidified to a highly deliquescent erystal- 
line mass. 
There can be no doubt that this consisted of the sulphate, 
—~ COOH = 
Gun) pot CO EOE SOO 
SO, 
but owing to its deliquescence it was not analysed. 
Ethyl-Chlorate of Triethyl-Phosphorus-Betaine.—This compound was pre- 
pared by Hormann, but was not obtained by him in the crystalline state (see 
p. 293). 
