STEAROPTENE OCCURRING IN ESSENTIAL OILS OF MYRTACEAE. 89 
6. (B) 0°1118 gram gave 0°2666 gram CO, and 0°0742 
gram H.O. O—65°04%, H—7°37 %. 
7. (B) 0°1164 gram gave 0°2792 gram CO, and 0°0794 
gram H.O. C—65°41%%, H—7°58%. 
O13His04 requires O=65°5555, H=7°567%. 
Molecular Weight Determinations. 
(a) A molecular weight determination by the Landsberger 
boiling point method using acetone as solvent gave the 
following result:—1 gram in 28°25 c.cs. acetone elevated 
the boiling point 0°33° C. M.Wt. 238°7. 
(b) A determination by the cryoscopic method using 
benzene resulted as follows:—0°2138 gram in 10°42 grams 
benzene lowered the freezing point of the solvent 0°43° CO. 
M.Wt. 238°6. 
O13HigO1 requires 238. 
Determinations of Methoxy Groups. 
The percentages of methoxyl (OCH;) obtained in three 
Zeisel determinations were 24°5, 25°4 and 26°2. Oj3His043 
2 0H;O requires OCH, = 26°057%. 
Judging from these estimations the stearoptene contains 
two methoxy groups. 
As the total amount of material at our disposal was so 
small, amounting to but 12 grams, we were unable to 
proceed further with the elucidation of the chemistry of 
this beautifully crystalline substance, and, therefore, defer 
the matter of suggesting a name for it until we succeed in 
discovering better sources of supply, which will then enable 
us to determine its molecular structure as well as its other 
characters, and confirm or otherwise our surmise that it is 
probably a phenol ether. 
