828 PROFESSOR CHRYSTAL AND MR E. MACLAGAN-WEDDERBURN 
The value of K(c, 1) is readily calculated by means of an ordinary table of logarithms 
together with Lecrnpre’s table for log I'(a).* 
Thus —_K(3°6284, 1) = 21'(2°2346)P'(-2654)/T'(1-7346)T( — 2346), 
2 x 1°7654 x +2346 x *76541(1-2346)1(1:2654) 
-26541(1°7346)1'(1:7654) ; 
Hence log { — K(3°6284, 1} ="21087 ; and K(3°6284, 1)= — 1°62507. 
The calculation of K(-7353 ,1) is even simpler. ; 
If x(c) = K(e, 1) + pK(c’, 1), where p = 2°2214, we have now the following table :— 
Te 8x66) Diff. 
144. | —-08755 08571 
14:5 | — 00174 08053 
146 | +-07879 
Hence, interpolating by means of the first difference, we get finally 
T, = 14-50". 
Also corresponding to the value of T,, we have 
€,=3°9775; c= "7250. 
§ 8. Brnopat PERiop OF Harn. 
4t c a 4(5 +a) F(5 — a) 4(3 +a) 4(38 — a) Ke 
8:10 11°4673 68461 2°9615 — 4615 2°4615 — 9615 + 40305 
8:14 11°3541 6°8130 2°9533 — 4533 2°4533 — 9533 + 48754 
8°20 11°1893 O10st. 2°0411 | —-4411 2°4411 — "9411 + 61286 
T c a ata’) | 4(5-a) | g8+a) 4(3 — a’) K(c, 1) 
8:10 93239 3°2087 2°0522 "4478 1 5522 — 0522 — 23022 
814 |; 2°3011 3°1944 2°0486 4514 15486 — 0486 — 21271 
8°20 2°2676 3°1734 2°0434 "4567 15434 — 0434 — "18800 
T x(¢) | Diff. for ‘01 
8:10 — 11105 03152 
8:14 + 01502 03014 
8:20 | +°19525 
T, = 8135’ =8'14’ say. 
¢)=11°3598; c', = 2°3022. 
* The abridgment in Wrntiamson’s Integral Calculus is convenient. I have noted two errors in it. Log 
r(1°573) should be 9°949761 ; and log 1(1°669), 9°955750. 
