SPECIFIC GRAVITY AND DISPLACEMENT OF SOME SALINE SOLUTIONS. 143 



R 



In the figure we have a hexagon the corners of which are numbered on this plan 

 from 1 to 6. hiside the hexagon we have the common element M 

 or R, and above it the value of m for the particular solution. The 

 residue corresponding to the lowest value of v/m is entered at the 

 corner numbered 1, the next higher at 2, the next at 3, and so on, 

 the residue corresponding to the highest value of i;/m occupying place 

 No. 6. For concentrations higher than m=\/64, the arrangement of 

 residues is the same as that given for m=l/64 in the six hexagons 

 corresponding to the common elements CI, Br, I, K, Rb, Cs. 



In the accompanying figures we have the three hexagons 1/64 [CI], 1/64 [Br], 

 1/64 [I] corresponding to the nuclei CI, Br, I, and to the value of m = 1/64. The 

 salts corresponding to the first hexagon are CIM and CIMO3. and their residues after 

 abstraction of CI are K, Rb, Cs, KO3, RbOg, CsOg. Entering these at the corners, on 

 the plan above explained, in ascending order of magnitude of t'/m, the residue corre- 

 sponding to the lowest value of v/m being entered at place 1 , we find that the order 

 in which the residues follow each other is that of the salts of the two triads CIM and 



KO, 



Cs 



CsO, 



Cs 



Rb 



1/64 

 CI 



RbO, 



CsO, 



K0„ 



Rb 



1/64 ^^^3 



Bp 



K 



CsO« 



K 



RbOo 



1/64 

 I 



Rb 

 Cs 



K 



KO, 



ClMOo, and following the ascendino; order of molecular weight in each triad. When 



the nucleus is Br, the order difi'ers from that corresponding to CI in that the neigh- 

 bouring residues Cs and KO3 change places. When the nucleus is I, the arrangement 

 seems to be quite diff'erent, but it is derived from that with the nucleus Br by replacing 

 at each corner the residues M by MO3 and MO3 by M. 

 If we arrange the residues in parallel lines we have : — 



Hexagon. 



Residues in ascending order of magnitude of v/m. 



1/64 [CI] 

 1/64 [BpI 

 1/G4 [I] 



K 



K 



KO3 



Rb 



Rb 



Rb03 



Cs 



KO3 



K 



KO3 



Cs 

 CSO3 



RbOg 



RbOg 



Rb 



CsOg 

 CSO3 



Cs 



When the metals act as nucleus, we have the hexagons in the figures on p. 144. 

 In each of these hexagons CI occupies place 1, Br place 2, and IO3 place 3. The 4th 

 place is occupied in the consecutive hexagons by CIO3, Br03, Br03 ; the 5th by BrOg, 

 CIO3, I ; and the 6th by I, I, CIO3. The hexagon 1/64 [K] is derived from 1/64 [CI] 

 by an exchange of place between I and IO3, which correspond to Cs and CsOg ; when 



