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I 
22 AUG. WIJKANDER. OBSERVATIONS METEOROLOGIQUES. 
p a 
Température de Ps 
Jour.  Minuit. dr 2" SME 5! 6' Zz 8" 9" 
o o I o o | o o o o o o 
I N33:5 RE SN RE —"3455 73860 —1 34:48 | 0348 308 — 84458 | NOG 
> 2 dt TS Hog ll LER LO = 0:85 == LOMI FA 2K9KS = R0:8 ="KLOH oo ne 
3 = 0 ENE a avd) = ROS = on = (ic0 = RON == 54:60 = K4:9 a 
4 = DJ FER dö = 100 Utg a Led SN GD =="B3E5 —L5:2 a ma Cd 
5 Ft 03:00 = A0:2 + FRSkO I Hd [EE 0.8 = 2 = "KA Nb) ER =HEEg 
6 fr ANA: LO gel — 4.85 | — 4.05 me 0 SE INREOS Fr = Hg 
7 FI KNISNO a EO: Fr NI250 = io SAN SR EIN ="MENY. IA MLS 
3 — CCG — 10.4 | = 10.55 =S: = ON dT ON EA = DO = TES 
9 = 05 TE CL) = IKE MIEE= 1 H0:0 = GÖ SE ej =E Ub = 05 15.8 IRA 
10 2 öl NR = RAS FT: ga = 16:0 — 1659 — SKA: = RILGRS == HIL6:6 a 
11 Lig VR = 2606 — 20.21 | — 21.84) — 21:4 | = Dog Pie AR a) 
12 = (2 LL g/SoR LL RN = PLA.4 TAN = ARSA) ARS nm CE) — 1454 LIG 
13 FRÄS: Fra SLA: far 1340 — 12.9 =1£8:618$| "== "BKÖSEK TORA — 16.4 AL4=850 | NER 
14 = ST ko Fr IG ONE RR —LALO TARA — 14.0 | — 14:8 | — 14:4 == 8:95 RE 
YS == leg KL: FE TIG:0ET I ID: SS NA TS BR [ 16.4 | = H6:2 = KE:9 49:60 
16 = = 1 8:9 == 10:3 ar NS-4 — 18.13) — 94 | ANNO | K9:9 — 0 9:4 = LEO: 
7 NÄE 34, = ii ST L2:4 = (205 —=H284 | FRA NR mn 0 
SET TAS | i KS: = MöL2 = flög — 17.7 0) — 182 HIS: 1 90 093 =KTH:O 
19 = ANN ESR = 02012 == 127:0 =126:9 126058 = OMS I Re 0052 -—3 20.8 
| I mA oc 
20 ANDA FSS — 336 = NR rB3:0 — 346 RA SVT älta 30-3 35-5 
21 AOL: — Zid SiIO = 030:5 —180:0 30:45 SR 5 90:0 =R30:6 
2 = joo 20: = 20H0 = 20 29.0 — 281 | — 27.2 RR: ===K0Y:O — 26:60 
23, |A 3459 NAO ESD: mg BS TSV ES I 2 = 807 ASS 
24 SON - 28/0:2) NN 2302 FT SS = 130:4, 9428 FA 3SE re 36.2 a GIN = 
25 030:0 = Se 3553 = dö = ND = 36:60 = AN för: 36.0 mn SO Og 
26 = AL LAN So OR — TEMA = NLO:S = N8:0 — 06.8 ST NG AO 
27 FL OR Ra — As: TG SA: = HO SV = LG = SY — 
28 20:00 NS: | SAG = Giger — gt — bye = pe mm =2L-3 =L10:7 
29) IEEE 3.9 Eran NER jgs — I 5:7a Nl =" ASR5 =! 14055 a GD No HG = HJ = 
30 — 16.0 | — 15.8 | — 15.6 ind a HN a DUR 1 TO NRO — LD: = 50 
31 — 15.1 | — 15:0 | — 13.8 — 12.4 | — 121 | — 12.269 = EG, | 245 NSD — 14.9 
Moy. | — 17.68 | — 17.57 | — 17.47 | — 17.67 | — 17.64 | — 18.21 |. — 18.35 | — 18.40 | — 18.42 | — 17.97 | 
AR D r 
Température de 
— = == ; — = i = — —— 
3 h h h h | h h h h J 
Jour. Minuit i 2 | Så 4' | 5 6 | TT 8 I 
Oo [0] [0] Oo lä Oo | Oo Oo I Oo Oo Oo 
I FI (050) =O = Ge = GA = AG JAG | 9-7 = (05 =? 1082 LIGEN NL 
2 SS JÄRN = 6.7 i UNS = SAD ÖN SR 140 = Hel SB (NR — MET 
3 57 (NOA k AN 18:06 a KE an rn AOR = (800) NEO GA) 
4 SE SÖ SA RME > JD = SEN AR = SKA — SÅR Ser 
5 ÖNS [Fr 8.3 F/D Ag mm VEN äng RE — = (KY 
6 SL | = AD RS EE DG Pe =G ST NG:O = VEG ON fd 
7 KAN I GD = gsDh HA — 6.5 — 4.2 = — 6.1 Sie) = 2 
8 00 | Fk 0-2 = 0:55) — 9-6 — TA-O — 16.6 | — 18:4 | — 19:9 — 21.4 | NN 202 
9 0-4 —120:4: ZON | 272 — ARN (NN ER 2ONLA MES N2I5E0 En = 
10 FS RVNA Fe RAG 20 = 1260:4; = 02608 = 20:40 — 12050 | — 2552 = VAA mm FSS 
11 LIA = Do SRA | — 22.8 = 231 | — 228 = NA 23 — ALS — 22.6 
12 = 20:0 = LOSS gb Ne it = 94 | — 19:90 = SIÖFSE ee 20:80 = 20:0 = N20:3 
IE Fe AA SS a VN KR De FO RSA = fare |" FRAs a kg =L235Z 
ZI RE = 010:8 = = ON ER | = 20:00 = 12030. Sr Tr 208 2005 TROR 
Hiss og = F—20:2 — 28.0 RN KI = 20 =S NN = Na Ne 
16 208 280 — 23.2 | — 23.6 = == AN REN = CK LOGGA RO 
17 | — 22.0 = 1260:0 ar = lg = gicks TN KL SN = NA: RNA = AK 
18 | Fr SA — 30.8 I 20 = Sjuton = J009 SING SON s030:6 a MA — Ne 
KOL 29.7 — 30:4 | 31.6 | — 30.8 31.6 30.1 a 750 = Nr = 
20 |fEr29:2 == 20 30.6 = fe FOJO NN 28.6 = 12052 = RRES IK 1206 
21 | 26.1 2 | = 2005 == Dl) = yr) | = 26.0 OA RS AR 
22 23-95 = 24.2 | "= 24.8 — 26.7 — 26.-9 — 26.8 — 25.8 | — 24.450 | — 23.1 | — 22.5 
23 SS OR = DE = 2010 7 Dot = Obol RAS —=N2358 = GO) — ED 
24 UN 208 27-4 27:0 = = go Ne TN I Sr NN FORT = OR 
ÅS 015-057 15.6 a HS — 14-15 — L4:0 RULAN Tr ls | 13.8 0 NAR — 
26 17.8 17.0 —— 1/5 = 16:6 = UD SS 0 — 168 ET SSR ES UN 
27 16.0 = MMA: YES TATE = EO SD = NLOTS 7 AS =" 16:9 170 
28 19.0 F-K20:0 = oa DR s 12358 SS = AD Er ND = Cy —H202 
29 000 ALS 20.3 FEELS: TIN = ATOL = EST — = TA 
30 | —:13.0 == NORD [2.5 = Lr = 128 = 0 0 AS AI 0 I 
Moy. Z 
