66 P. T. CLEVE. 



The theory requires: 



Experiment 

 Cleve Peyrone 



Platinum 65,35 64,94 65,25 



Chlorine 23, 12 23,74 23,46 



It is worth notice that the chloroplatinite contains two molecules of the chloride 

 of platomonodiamraine. Diammonia probably seems to be necessary for the formation 

 of double chlorides of the bases of platinum. 



3. Nitrate, R . 2 . 2N0 2 J -H 2 0, was obtained by double decomposition of the 



chloroplatinite and nitrate of silver. The solution filtered from the precipitate of 

 chloroplatinite of silver was evaporatcd in the water-bath, the remaining saline mäss 

 washed with alcohol, and then dissolved in water. The solution left to spontaneous 

 evaporation yields white or light-yellow crusts, which appeared, when examined with 

 the microscope, to be a confused heap of thin scales. When heated, the nitrate is de- 

 composed with violence. It is directly united with bromine and gives bromonitrate of 

 platinmonodiammine. 



Analysis, the nitrate being dried över sulphuric acid: 

 a. 0,3000 gr. gave 0,i.v.'0 gr. metallic platinum. 

 1). 0,3855 gr. gave 61 C. C. nitrogen (temp. of the water 18°. Bar. 757 m.m. t. 



15°) ^0,0699 gr. nitrogen. 



The formula requires: 



Theory Experiment 



a b 



Platinum 197,88 — 50,52 50,i>7 — 



Nitrogen 70,oo — 17,91 18,13 



Hy drogen 11, 00 



Oxygen 1 12, 00 



390,88 



4. Sulphate, R . O* . S0 2 , is prepared by boiling the chloroplatinite with sulphate 

 of silver and evaporating the liquid. The sulphate forms snow-white crusts of mi- 

 croscopical needles and is not very easily soluble in cold, but far better in boiling 

 water. 



Analysis: the sulphate dried at 100°. 



a. 0,4050 gr. gave 0,2:?oo gr. platinum and 0,2850 gr. sulphate of barium = 0,0391 gr. 

 sulphur. 



b. 0,2*70 gr. gave 28,5 C. C. nitrogen (temp. of water 18° Bar. 765 m.m. t. 17°) 



0,0330 gr. nitrogen. 



The formula requires: 



