ON THE MERIDIAN. 



107 



1 

 Now the meafure oF the firfl: degree or X is 60472 83 fathoms arid 



n=g. Therefore n X~ 544255.47 which fubtracted horn A or 



(I) 

 544433.208 gives 177.74 ■= A^—nX. 



(V (1) 



And Sin.'' I — Sin.* / —, 00^014 •.♦, 006014 X 177.74 = i.cGS^a'S^ 



(1) . Ci) (1) 



equal {A — n X) , (Sin.* / — Sin.* /) the numerator; and thedenomi- 



(2) fl) (3) (1) (4) (I| 



nator (Sin.*/ — Sm.^ /; 4- (Sin.* ^ -^ Sin.'/, -|- (Sin.» l-^S'm.'i 



f9) . (1) 



Sec, . . . • (Sin.*/ — Sin,* /) is ,2631370. 



Hence- 



(A — nX) .{Sin. 2 / — Sln.*^/; 



1.0689284 



; 4.05225 — <?^' 



i(i) ( ) i^) (1) 



.|Sin.^ / — Sia,* -h . . . (Sin.* / — Sin.^ I) ,?63137 



;find- 



4.06225 





-675.47 =r a 



,.c0060l< 



TABLE I. 



Degree in Fatfiamt. 



Letiiitti, 



,,*,,......,.......,,.......-.,. 60472.83 , ,«.T;r? 5> 34 44 



X = X ^ ..... 



X = X 4- d ....^ ...., .-,...,. 60476.89 „..,., 10 34 44 



,{3) (1) f3) (1.) 

 X == X + e (Siu.M — Sin.' /J ..«..., ^.^...... 60481.34 ♦,,.,.. ,..^, 11 34 44 



(4) (I) ^ (<) ^ (1| 



X = X + e (Sin.* / — Sin.« /) ............ ...60486.16 «,.. 12 34 44 



(5) (1) (6) (1) 



X = X -{- Q (Sin.M — Sin.« /) ....'........,..,.0..,. 60491.36 ,, ....... .^. 13 34 44 



^6) (\) .(6) (1) 



X = X .4- Q (5Id.» / — Sin.' I) ., 



.... 60496.92 ««•..,«..... 14 34 



47) (I) (7) (1) 



X — X + 42 (Sio.^ /— Sin.= i) ..,.,.......,. ..<vc. ..,».: 6G502.85 •*«, ^.15 34 44 



(8) (') (») CD , ,, 



X =: X rf -Q (Sin.' / — Sin.-« Z) €0509.12 .....16 34 4i 



>(9) (!) (9) m 



>•« • . • . •-«-» 



.60515.74 , 17 34 <4 



.544433.21 cr A 



