weight of water (W ) = (volume of sample w/ice) (porosity) (water density) 



w 



K w . (24-4) (48-4) (18-2) (0.3, (62.4)/l,728 



W = 152 lb or 69 kg 



w 6 



Calculations for the cooling requirements are shown below: 



Cooling water and rock to 0°C plus ice: 



Water 40° to 32°F (4.5° to 0°C) 



AH = (W ) (C ) (At) 



w pw 



= (152) (1) (8) 



1,216 Btu or 1.28 MJ 



Water to ice AH (W ) (heat of fusion) 



w 



= (152) (144) 



21,888 Btu or 23.1 MJ 



Rock 40° to 32°F (4.5° to 0°C) 



AH = (W r ) (C ) (At) 



= (1,380) (0.2) (8) 



2,208 Btu or 2.33 MJ 



Total to freeze = 25,312 Btu or 26.7 MJ 



Cooling ice and rock to 0°F (-18°C): 



Ice 32° to 0°F (0° to -18°C) 



AH = (W ) (C .) (At) 



w pi 



(152) (0.48) (32) 

 2,335 Btu or 2.46 MJ 



Rock 32° to 0°F (0° to -18°C) 



AH = (W r ) (C ) (At)/ 1,000 



(1,380) (0.2) (32) 

 8,832 Btu or 9.3 MJ 

 Total 32° to 0°F (0° to -18°C) = 11,167 Btu or 11.76 MJ 

 TOTAL COOLING REQUIREMENT 



40° to 0°F (4.5° to -18°C) 36,479 Btu or 38.47 MJ 



3 



