186/.] 



Extractive Matters of Urine. — Part I. 



97 



In 100 parts it contained therefore 



C 18-07 



H 2-24 



N 0-78 



2212 



PbO 53-63 



PbCl 3^16 



100-00 



Though the substance combined in this case Vvith the oxide and chloride 

 of lead was without doubt a mixture, still I think it may be of use to 

 devise some formula which shall express its composition, and thus lead to 

 some plausible conjecture as to its constituents. The relatively large 

 quantity of oxygen contained in it makes this rather difficult ; but, as I 

 shall presently show, one of the urinary extractive matters is richer in 

 oxygen than the others, and by assuming that the substance in this case 

 was a mixture of equal parts of this extractive matter and glucose, I arrive at 

 the formula C.^ H^g NO^^, which requires 



Calculation. Experiment. 



C^, '300 42-55 41-81 



rigg 39 5-53 5-18 



N 14 rOS 1-80 



O,, 352 49-94 51-21 



705 100-00 100-00 

 The hquid filtered from this lead compound did in fact contain a sub- 

 stance having the com.position of glucose. On adding to it an excess of 

 ammonia, a bulky precipitate fell, which was filtered off and treated with 

 a mixture of alcohol and acetic acid, in which almost the whole dissolved. 

 To the filtered liquid there was added a small quantity of ammonia, which, 

 produced an almost white precipitate. This was filtered off, washed with 

 alcohol, dried in vacuo, and analyzed. 



1*3730 grm. of this precipitate gave 0*6585 grm. carbonic acid and 

 0*2265 grm. water. 



2*0730 grms. gave 0*0600 grm. chloride of platinum and ammonium. 

 0*7945 grm. gave 0-7/20 grm. sulphate of lead. 

 In 100 parts the compound contained therefore 



C 13*08 



H 1-83 



N 0-18 



13*42 



PbO 71*49 



100-00 



If the small percentage of nitrogen, which was probably due to an 

 admixture of extractive matter be neglected, this composition leads to 

 the formula C^iH^gO^g + 7PbO, which requires 



